Re: column totals
| От | Ragnar |
|---|---|
| Тема | Re: column totals |
| Дата | |
| Msg-id | 1148660617.8566.51.camel@localhost.localdomain обсуждение исходный текст |
| Ответ на | column totals (James Neethling <james@silversphere.co.za>) |
| Список | pgsql-performance |
On fös, 2006-05-26 at 11:56 +0200, James Neethling wrote:
> SELECT branch_id, prod_cat_id, sum(prod_profit) as prod_cat_profit
> FROM () as b1
> WHERE x = y
> GROUP BY branch, prod_cat_id
>
>
> Now, I also need the branch total, effectively,
> SELECT branch_id, sum(prod_profit) as branch_total
> FROM () as b1
> WHERE x = y
> GROUP BY branch_id.
>
>
> Since the actual queries for generating prod_profit are non-trivial, how
> do I combine them to get the following select list?
one simple way using temp table and 2 steps:
CREATE TEMP TABLE foo AS
SELECT branch_id,
prod_cat_id,
sum(prod_profit) as prod_cat_profit
FROM () as b1
WHERE x = y
GROUP BY branch, prod_cat_id;
SELECT branch_id,
prod_cat_id,
prod_cat_profit,
branch_total
FROM foo as foo1
JOIN
(SELECT branch_id,
sum(prod_cat_profit) as branch_total
FROM foo
GROUP BY branch_id
) as foo2 USING branch_id;
(untested)
gnari
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