Re: How to get a count() where column < ''?
От | Joost Kraaijeveld |
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Тема | Re: How to get a count() where column < ''? |
Дата | |
Msg-id | 1133732596.5560.11.camel@Panoramix обсуждение исходный текст |
Ответ на | Re: How to get a count() where column < ''? (Stephan Szabo <sszabo@megazone.bigpanda.com>) |
Ответы |
Re: How to get a count() where column < ''?
Re: How to get a count() where column < ''? |
Список | pgsql-sql |
Hi Stephan, On Sun, 2005-12-04 at 13:33 -0800, Stephan Szabo wrote: > > SELECT COUNT(customers.objectid) FROM prototype.customers, > > prototype.addresses > > WHERE > > customers.contactaddress = addresses.objectid > > AND > > zipCode < '2716BN' > > ORDER By zipCode, houseNumber > In a non-grouped query like the above, I don't think that the order by is > meaningful. You only get one row back anyway without a group by, and > there's no single zipCode or houseNumber to associate with the row. > What do you mean by a non-grouped query? The query below gives the same error: SELECT zipcode, COUNT(*) FROM prototype.customers, prototype.addresses WHERE customers.contactaddress = addresses.objectid AND zipCode < '2716BN' -- Groeten, Joost Kraaijeveld Askesis B.V. Molukkenstraat 14 6524NB Nijmegen tel: 024-3888063 / 06-51855277 fax: 024-3608416 e-mail: J.Kraaijeveld@Askesis.nl web: www.askesis.nl
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