Re: [HACKERS] postgres_fdw bug in 9.6
| От | Tom Lane |
|---|---|
| Тема | Re: [HACKERS] postgres_fdw bug in 9.6 |
| Дата | |
| Msg-id | 10840.1482161852@sss.pgh.pa.us обсуждение исходный текст |
| Ответ на | Re: [HACKERS] postgres_fdw bug in 9.6 (Etsuro Fujita <fujita.etsuro@lab.ntt.co.jp>) |
| Ответы |
Re: [HACKERS] postgres_fdw bug in 9.6
|
| Список | pgsql-hackers |
Etsuro Fujita <fujita.etsuro@lab.ntt.co.jp> writes:
> On 2016/12/17 1:13, Tom Lane wrote:
>> So I think the rule could be
>> "When first asked to produce a path for a given foreign joinrel, collect
>> the cheapest paths for its left and right inputs, and make a nestloop path
>> (or hashjoin path, if full join) from those, using the join quals needed
>> for the current input relation pair.
> Seems reasonable.
>> Use this as the fdw_outerpath for
>> all foreign paths made for the joinrel."
> I'm not sure that would work well for foreign joins with sort orders.
> Consider a merge join, whose left input is a 2-way foreign join with a
> sort order that implements a full join and whose right input is a sorted
> local table scan. If the EPQ subplan for the foreign join wouldn't
> produce the right sort order, the merge join might break during EPQ
> rechecks (note that in this case the EPQ subplan for the foreign join
> might produce more than a single row during an EPQ recheck).
How so? We only recheck one row at a time, therefore it can be claimed to
have any sort order you care about.
regards, tom lane
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