Re: Multicolumn foreign keys need useless unique indices?

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От
Hannu Krosing
Тема
Re: Multicolumn foreign keys need useless unique indices?
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Msg-id
1032025638.3025.10.camel@rh72.home.ee
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Multicolumn foreign keys need useless unique indices? Antti Haapala <antti.haapala@iki.fi>
Re: Multicolumn foreign keys need useless unique indices? "Christopher Kings-Lynne" <chriskl@familyhealth.com.au>
Re: Multicolumn foreign keys need useless unique indices? Rod Taylor <rbt@rbt.ca>
Re: Multicolumn foreign keys need useless unique indices? Tom Lane <tgl@sss.pgh.pa.us>
Re: Multicolumn foreign keys need useless unique indices? Hannu Krosing <hannu@tm.ee>
Re: Multicolumn foreign keys need useless unique indices? Rod Taylor <rbt@rbt.ca>
Re: Multicolumn foreign keys need useless unique indices? Hannu Krosing <hannu@tm.ee>
Re: Multicolumn foreign keys need useless unique indices? Tom Lane <tgl@sss.pgh.pa.us>
Re: Multicolumn foreign keys need useless unique indices? Hannu Krosing <hannu@tm.ee>
Re: Multicolumn foreign keys need useless unique indices? Tom Lane <tgl@sss.pgh.pa.us>
Re: Multicolumn foreign keys need useless unique indices? Stephan Szabo <sszabo@megazone23.bigpanda.com>
Re: Multicolumn foreign keys need useless unique indices? Antti Haapala <antti.haapala@iki.fi>
Re: Multicolumn foreign keys need useless unique indices? Stephan Szabo <sszabo@megazone23.bigpanda.com>
On Sat, 2002-09-14 at 20:14, Tom Lane wrote:
> Hannu Krosing  writes:
> > If we have unique index on t.i and we define additional unique
> > constraint on (t.i, t.j), then we don't need the extra unique index to
> > be created - the index on t.i is enough to quarantee the uniqueness of
> > (t.i,t.j) or any set of columns that includes t.i.
> 
> You missed the point: we are concerned about existence of a row, not only
> uniqueness.

Maybe I'm missing something, but I'll reiterate my two points

1) to check for existance of a referenced tuple for a foreigh key we
have to:

* lookup the row in index

and

* check if the row is live in the relation

so the index will help us equally for both cases, as it will point to N
entries of which only one can be alive at a time and which all have to
be checked.

It will be only marginally more work to check if the only live entry
does match the non-index columns.


And I think that my other point holds as well - there is no need for
extra unique index on (redundant) unique constraint that is put over a
superset of columns covered by _another_ unique constraint. 

There will probably be additional work if we want to drop the original
constraint, but this is a separate issue.

---------------
Hannu



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