Trouble with SQL statement using variable
| От | Jeff Self |
|---|---|
| Тема | Trouble with SQL statement using variable |
| Дата | |
| Msg-id | 1012329292.14152.5.camel@personnel_test обсуждение исходный текст |
| Ответы |
Re: Trouble with SQL statement using variable
Re: Trouble with SQL statement using variable |
| Список | pgsql-php |
I'm having trouble getting an SQL statement to use a variable. Here's
the statement:
$sql = "SELECT emp_fname FROM employee WHERE username = '$username'";
$result = pg_exec($conn,$sql);
if (!$result) {
exit;
}
I get the following warning from this:
Warning: Supplied argument is not a valid PostgreSQL link resource in
/var/www/personnel/include/functions.inc on line 25
Is there another way to use a variable in an SQL statement. This format
works with MySQL.
--
Jeff Self
Information Technology Analyst
Department of Personnel
City of Newport News
2400 Washington Ave.
Newport News, VA 23607
757-926-6930
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