PLSQL function calling another function
| От | |
|---|---|
| Тема | PLSQL function calling another function |
| Дата | |
| Msg-id | 092C17F5803E42FCAFD8D3A43A2E5A12@nc05072019 обсуждение исходный текст |
| Ответ на | logging SQL statements ("c k" <shreeseva.learning@gmail.com>) |
| Ответы |
Re: PLSQL function calling another function
|
| Список | pgsql-general |
Hi All,
I am trying to figure out how to call one PLSQL function from another, specifically how to access the return values from the callee.
I made two test functions, A and B. A calls B.
B returns two values:
OUT tid integer
OUT msg character varying
In caller function A, I do the following:
SELECT B(1) INTO rec; -- rec declared as a RECORD
RAISE DEBUG 'XXX % [%]', rec.tid, rec.msg;
RAISE DEBUG 'XXX % [%]', rec.tid, rec.msg;
The runtime error I got was:
ERROR: record "rec" has no field "tid"
SQL state: 42703
SQL state: 42703
The full function code is below.
Thanks,
CYW
--------------------------------
FUNCTION B(IN id integer, OUT tid integer, OUT msg character varying) RETURNS record AS BODY$
DECLARE
DECLARE
BEGIN
msg := 'MSG';
tid := 100;
RETURN;
END;
msg := 'MSG';
tid := 100;
RETURN;
END;
FUNCTION A(IN x integer, IN "text" character varying, OUT whatever character varying) RETURNS character varying AS $BODY$
DECLARE
rec RECORD;
tid int4;
msg varchar;
BEGIN
SELECT B(1) INTO rec;
RAISE DEBUG 'XXX % [%]', rec.tid, rec.msg;
RETURN;
END;
DECLARE
rec RECORD;
tid int4;
msg varchar;
BEGIN
SELECT B(1) INTO rec;
RAISE DEBUG 'XXX % [%]', rec.tid, rec.msg;
RETURN;
END;
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