RE: Still don't know how to build this string ?

Still learning this stuff, so please be gentle...


jeff=# select * from test_it;typ | diam 
-----+------01  | 80001  | 84001  | 87001  | 112002  | 76002  | 78002  | 80002  | 90003  | 120003  | 123403  | 1352
(11 rows)

jeff=# \! cat test_it
drop function test_it_too(text);
create function test_it_too(text)
returns text as '
declare 
typ2 alias for $1;
rec record;
string text:= '''';
begin
for rec in select * from test_it where typ = typ2 loop
string := string || rec.diam || '','';
end loop;
string := substr(string, 1, length(string)-1);
return string;
end;
' language 'plpgsql';

jeff=# \i test_it
DROP
CREATE
jeff=# select test_it_too('01');  test_it_too    
------------------800,840,870,1120
(1 row)



> -----Original Message-----
> From:    juerg.rietmann@pup.ch [SMTP:juerg.rietmann@pup.ch]
> Sent:    Monday, March 26, 2001 4:13 AM
> To:    pgsql-sql@postgresql.org
> Subject:    Still don't know how to build this string ?
> 
> Hello there
> 
> I have still the same problem. Any help would really be appreciated !
> Thanks ... jr
> 
> Is it possible (and I think it is) to do the following :
> 
> I have a table with diameters and types. I need to build a comma separated
> string.
> 
> typ       diam
> 01        800
> 01        840
> 01        870
> 01        1120
> 02        760
> 02        780
> 02        800
> 02        900
> 03        1200
> 03        1234
> 03        1352
> 
> select diam from zylinder where typ='01'
> 
> should produce the string "800,840,870,1120"
> 
> 
> 
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