Re: 7.3 "group by" issue
От | Chad Thompson |
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Тема | Re: 7.3 "group by" issue |
Дата | |
Msg-id | 04f401c2d9e3$f24c1070$32021aac@chad обсуждение исходный текст |
Ответ на | Re: 7.3 "group by" issue ("Dan Langille" <dan@langille.org>) |
Ответы |
Re: 7.3 "group by" issue
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Список | pgsql-sql |
> On 21 Feb 2003 at 19:18, Gaetano Mendola wrote: > > > > Hi folks, > > > > > > This query: > > > > > > SELECT element_id as wle_element_id, COUNT(watch_list_id) > > > FROM watch_list JOIN watch_list_element > > > ON watch_list.id = watch_list_element.watch_list_id > > > AND watch_list.user_id = 1 > > > GROUP BY watch_list_element.element_id > > > > Try: > > > > SELECT element_id as wle_element_id, COUNT(watch_list_id) > > FROM watch_list JOIN watch_list_element > > ON watch_list.id = watch_list_element.watch_list_id > > WHERE > > watch_list.user_id = 1 > > GROUP BY watch_list_element.element_id > > ERROR: Attribute unnamed_join.element_id must be GROUPed or used in > an aggregate function > I think that the wrong problem was solved here. Items in the order by clause must be in the target list. heres what it says in the docs *The ORDER BY clause specifies the sort order: *SELECT select_list * FROM table_expression * ORDER BY column1 [ASC | DESC] [, column2 [ASC | DESC] ...] *column1, etc., refer to select list columns. These can be either the output name of a column (see Section 4.3.2) or the number of a column. Some examples: Note that "column1, etc., refer to select list" HTH Chad
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