Re: count and group by question
От | Rod Taylor |
---|---|
Тема | Re: count and group by question |
Дата | |
Msg-id | 03ac01c217e7$ebbbe8c0$fe01a8c0@jester обсуждение исходный текст |
Ответ на | Re: count and group by question ("Dann Corbit" <DCorbit@connx.com>) |
Список | pgsql-hackers |
Make the whole thing a subselect in the from, and count that. select count(*) from (<other query>) as tab -- Rod ----- Original Message ----- From: "Ryan Mahoney" <ryan@paymentalliance.net> To: "Dann Corbit" <DCorbit@connx.com> Cc: "Hannu Krosing" <hannu@tm.ee>; <pgsql-hackers@postgresql.org> Sent: Wednesday, June 19, 2002 7:00 PM Subject: Re: [HACKERS] count and group by question > OK, so I tried both queries but they don't meet my requirement, I think > I wasn't clear. The methods suggested both return the aggregate count > as if the rows had not been grouped. What I am looking for is a count > of how many rows were returned *with* the grouping. > > So, suppose there are 1000 orders total, but when grouped by product 200 > rows are returned. I am trying to find a way to get that 200 not the > original 1000 count. > > Does this make sense? The Union was really interesting, I haven't used > union very much - but I will now! > > Thanks for your suggestions! > > -r > > > > SELECT > > > to_char(pa_shopping_cart.delivery_date, 'FMMM/FMDD/YY') AS > > > delivery_date, > > > pa_products.product_name AS product_name, > > > pa_orders.order_state AS state, > > > count(*) AS count > > > FROM > > > pa_shopping_cart, > > > pa_products, > > > pa_orders > > > WHERE > > > pa_shopping_cart.order_id = pa_orders.order_id AND > > > pa_shopping_cart.product_id = pa_products.product_id > > > GROUP BY > > > pa_shopping_cart.delivery_date, > > > pa_products.product_name, > > > pa_orders.order_state > > > > > > UNION > > > SELECT > > > NULL,NULL,NULL, count > > > from ( > > > select count(*) AS count > > > FROM > > > pa_shopping_cart, > > > pa_products, > > > pa_orders > > > WHERE > > > pa_shopping_cart.order_id = pa_orders.order_id AND > > > pa_shopping_cart.product_id = pa_products.product_id > > > ) total > > > > > > ORDER BY > > > pa_shopping_cart.delivery_date, pa_products.product_name; > > > > > > make the NULL,NULL,NULL part something else to get it sorted where you > > > want. > > > ---------------------------(end of broadcast)--------------------------- > TIP 2: you can get off all lists at once with the unregister command > (send "unregister YourEmailAddressHere" to majordomo@postgresql.org) >
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