hello,
I did now:
select foo,count(foobar),length(foo) from bar where foobar like 'foobar%' group by foo;
foo | count | length
------------------------
090700 | 494 | 6
090701 | 6 | 6
090702 | 4 | 6
090700 | 237 | 6
AAAAAAAAAA!!!!!!
now I found it!!!! User-input error: someone entered O90700 instead of 090700
with an 'O' (big 'o') instead of '0' (zero).... going crazy here.....
excuse me for this stupid question....
Mit freundlichem Gruß
Henrik Steffen
Geschäftsführer
top concepts Internetmarketing GmbH
Am Steinkamp 7 - D-21684 Stade - Germany
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----- Original Message -----
From: "Stephan Szabo" <sszabo@megazone23.bigpanda.com>
To: "Henrik Steffen" <steffen@city-map.de>
Cc: "pg" <pgsql-general@postgresql.org>; "Sönke Ruempler" <soenke@ruempler.de>
Sent: Thursday, July 25, 2002 5:55 PM
Subject: Re: [GENERAL] select distinct error ?
> On Thu, 25 Jul 2002, Henrik Steffen wrote:
>
> > select distinct foo from bar where foobar like 'foobar%';
> >
> > gives:
> >
> > foo
> > --------
> > 090700
> > 090701
> > 090702
> > 090700
> > (4 rows)
> >
> > foo is character(6)
> >
> > How can this happen??
>
> Do you have a simple dataset that you can replicate this with
> that you can send a dump of (tables, data). Also, what version
> and what locale are you running with?
>
>
>
>