RE: SQL statement PREPARE does not work in ECPG
От | Matsumura, Ryo |
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Тема | RE: SQL statement PREPARE does not work in ECPG |
Дата | |
Msg-id | 03040DFF97E6E54E88D3BFEE5F5480F737AA7C60@G01JPEXMBYT04 обсуждение исходный текст |
Ответ на | SQL statement PREPARE does not work in ECPG ("Takahashi, Ryohei" <r.takahashi_2@jp.fujitsu.com>) |
Ответы |
Re: SQL statement PREPARE does not work in ECPG
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Список | pgsql-hackers |
Hi I think SQL statement PREPARE *without* parameter is supported, but one with parameter is not supported (or has some fatal bugs). Because route for SQL statement PREPARE (line-1837 of preproc.y) always has output an invalid SQL statement and there is no regression test for SQL statement PREPARE. [preproc.y] 1832 | PrepareStmt 1833 { 1834 if ($1.type == NULL || strlen($1.type) == 0) 1835 output_prepare_statement($1.name, $1.stmt); 1836 else 1837 output_statement(cat_str(5, mm_strdup("prepare"), $1.name, $1.type, mm_strdup("as"), $1.stmt), 0, ECPGst_normal); 1838 } The next is log of ECPGdebug() and PQtrace() for the following statement. exec sql prepare st(int) as select col1 from foo; [14968]: ecpg_execute on line 17: query: prepare "st" ( int ) as " select 1 "; with 0 parameter(s) on connection conn To backend> Msg Q To backend> "prepare "st" ( int ) as " select 1 "" To backend> Msg complete, length 42 2019-02-19 06:23:30.429 UTC [14969] ERROR: syntax error at or near "" select 1 "" at character 25 2019-02-19 06:23:30.429 UTC [14969] STATEMENT: prepare "st" ( int ) as " select 1 " Regards Ryo Matsumura
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