Re: using calculated column in where-clause

> -----Mensaje original-----
> De: Scott Marlowe [mailto:scott.marlowe@gmail.com]
> Enviado el: Miércoles, 18 de Junio de 2008 17:47
> Para: Fernando Hevia

> >
> > For complex calculations I have obtained better performance using
> > nested queries. For example:
> >
> > select a, b, c select
> >   ( select a, b, a*b as c from ta) subquery1 where c = 2;
> >
> > This nesting is probably overhead in such a simple case as
> this, but
> > in more complex ones and specially with volatile functions it will
> > provide an improvement.
>
> I was under the impresion from previous discussions that the
> query planner flattened these out to be the same query.  Do
> you get different query plans when you re-arrange this way?
>

Take a look at this example (tried on 8.2.7 & 8.1.11):

create or replace function test(p1 integer, p2 integer) returns integer[] as
$BODY$
declare  retval   integer[];
begin  raise info 'called test(%, %)', p1, p2;  retval[0] = p1 + p2;  retval[1] = p1 * p2;  retval[2] = p1 - p2;
returnretval; 
end;
$BODY$
LANGUAGE 'plpgsql' IMMUTABLE;

-- In this case function test is called three times:
pg=# select (test(1, 2))[0] as sum, (test(1, 2))[1] as prod, (test(1, 2))[2]
as dif;
INFO:  called test(1, 2)
INFO:  called test(1, 2)
INFO:  called test(1, 2)sum | prod | dif
-----+------+-----  3 |    2 |  -1
(1 row)


-- In this case function test is called only once:
pg=# select res[0] as sum, res[1] as prod, res[2] as dif from
pg-# (select (test(1, 2))::integer[] as res) t ;
INFO:  called test(1, 2)sum | prod | dif
-----+------+-----  3 |    2 |  -1
(1 row)

I assume the second form will perform better since test is being called only
once.
I might be missing something in this assumption but at first glance it seems
pretty straightforward.

Regards,
Fernando.