I was able to do this with following query
select max(paymentid) as paymentid
from
(
select paymentid ,customerid
from tblpayment
except
(select max(paymentid) as paymentid, customerid
from tblpayment
)
) as this
group by customerid
This will get me the max for each customer yet I need it for each month so I could run this query for each month which is much better that on for each customer I think that I can get it better though.
David Blood
Boise, ID
I would like to be a ble to get a bunch of payments from a payment table. I want to return not the last payment the payment before that for all customers.
I have tried
select max(paymentid) as paymentid
from tblpayment
where paymentdebit > 0
and paymentid not in (select max(paymentid) as paymentid
from tblpayment
where paymentdebit > 0
group by customerid)
the cost on this thru the roof
NOTICE: QUERY PLAN:
Aggregate (cost=1520829785.44..1520829785.44 rows=1 width=4)
-> Seq Scan on tblpayment (cost=0.00..1520829707.94 rows=31002 width=4)
SubPlan
-> Materialize (cost=10336.74..10336.74 rows=6200 width=8)
-> Aggregate (cost=10026.72..10336.74 rows=6200 width=8)
-> Group (cost=10026.72..10181.73 rows=62005 width=8)
-> Sort (cost=10026.72..10026.72 rows=62005 width=8)
-> Seq Scan on tblpayment (cost=0.00..5091.10 rows=62005 width=8)
the same query rewritten using exist has a better time but still much to long
NOTICE: QUERY PLAN:
Aggregate (cost=5769119.39..5769274.41 rows=3100 width=8)
-> Group (cost=5769119.39..5769196.90 rows=31002 width=8)
-> Sort (cost=5769119.39..5769119.39 rows=31002 width=8)
-> Seq Scan on tblpayment thismonth (cost=0.00..5766806.60 rows=31002 width=8)
SubPlan
-> Limit (cost=39.16..39.16 rows=1 width=12)
-> Sort (cost=39.16..39.16 rows=5 width=12)
-> Index Scan using tblpayment_idx on tblpayment (cost=0.00..39.11 rows=5 width=12)
EXPLAIN
is there a better way to get the max - 1?
I could loop through and run the queriy for each customer but the cost on ten thousand quesries is rather high also?
David Blood
Boise, ID
David Blood
Boise, ID