Re: problem of geometric operator in v8.2.1
От | Ioseph Kim |
---|---|
Тема | Re: problem of geometric operator in v8.2.1 |
Дата | |
Msg-id | 010301c74710$161767f0$1e00a8c0@IDC обсуждение исходный текст |
Ответ на | problem of geometric operator in v8.2.1 ("Ioseph Kim" <pgsql-kr@postgresql.or.kr>) |
Список | pgsql-hackers |
I misunderstood. :) path '((0,0),(1,0))' is 'closed' path. in this case, it's maybe operator calculated return length too. ----- Original Message ----- From: "Ioseph Kim" <pgsql-kr@postgresql.or.kr> To: <pgsql-hackers@postgresql.org> Sent: Saturday, February 03, 2007 6:00 AM Subject: Re: [HACKERS] problem of geometric operator in v8.2.1 > when @-@ operator used at path type, > below query maybe returns 1. > because this path is just line. > > > ----- Original Message ----- > From: "Tom Lane" <tgl@sss.pgh.pa.us> > To: "Ioseph Kim" <pgsql-kr@postgresql.or.kr> > Cc: <pgsql-hackers@postgresql.org> > Sent: Saturday, February 03, 2007 5:36 AM > Subject: Re: [HACKERS] problem of geometric operator in v8.2.1 > > >> "Ioseph Kim" <pgsql-kr@postgresql.or.kr> writes: >>> => select @-@ lseg '((0,0),(1,0))'; >>> ?column? >>> ---------- >>> 1 >>> (1 row) >> >>> => select @-@ path '((0,0),(1,0))'; >>> ?column? >>> ---------- >>> 2 >>> (1 row) >> >>> It's maybe bug in v8.2.1 >> >> What do you think is wrong with those answers? >> >> regards, tom lane >> >> ---------------------------(end of broadcast)--------------------------- >> TIP 2: Don't 'kill -9' the postmaster >> > > ---------------------------(end of broadcast)--------------------------- > TIP 5: don't forget to increase your free space map settings >
В списке pgsql-hackers по дате отправления: