Re: Outer Joins

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От
Robert B. Easter
Тема
Re: Outer Joins
Дата
Msg-id
0101271913560W.08820@comptechnews
Ответ на
Re: Outer Joins (Bruce Momjian)
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Дерево обсуждения
Re: Outer Joins "Poul L. Christiansen" <poulc@cs.auc.dk>
Re: Outer Joins "Robert B. Easter" <reaster@comptechnews.com>
Re: Outer Joins Tom Lane <tgl@sss.pgh.pa.us>
Re: Outer Joins "Robert B. Easter" <reaster@comptechnews.com>
Re: Outer Joins "Robert B. Easter" <reaster@comptechnews.com>
Re: Outer Joins Tom Lane <tgl@sss.pgh.pa.us>
Re: Outer Joins "Robert B. Easter" <reaster@comptechnews.com>
Re: Outer Joins Tom Lane <tgl@sss.pgh.pa.us>
Re: Outer Joins Bruce Momjian <pgman@candle.pha.pa.us>
Re: Outer Joins "Robert B. Easter" <reaster@comptechnews.com>
Re: Outer Joins Tom Lane <tgl@sss.pgh.pa.us>
Re: Outer Joins Bruce Momjian <pgman@candle.pha.pa.us>
Re: Outer Joins Tom Lane <tgl@sss.pgh.pa.us>
JRelationalFramework Erik Tennant <lists@webpd.com>
Re: Outer Joins "Brett W. McCoy" <bmccoy@chapelperilous.net>
On Tuesday 23 January 2001 11:30, Bruce Momjian wrote:
> Can someone explain why cname and date from table c gets printed in this
> query?

The query was supposed to be:

SELECT * FROM a FULL OUTER JOIN b USING (id)
������� RIGHT OUTER JOIN c USING(id);

I missed the end of it when I was writing the email.

> > SELECT * FROM a FULL OUTER JOIN b USING (id)  <-- no ';'

> >  id | name | aname  | name | bname  | name |  cname  |    date
> > ----+------+--------+------+--------+------+---------+------------
> >   1 | Bob  | aname1 | Bob  | bname1 | Bob  | cname1  | 2001-01-07
> >   2 | Jim  | aname2 | Tom  | bname2 | Jim  | cname2  | 2001-01-07
> >   9 |      |        |      |        | Tom  | cname9  | 2001-01-07
> >  10 |      |        |      |        |      | cname10 | 2001-01-07
> > (4 rows)
>
> ---------------------------------------------------------------------------
>

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