I am sorry. I didn't read the doc properly. I understood why it is written
in that way.
Sorry for the trouble. Thanks. It worked fine for me.
Thanks
Kumar
----- Original Message -----
From: "Kumar" <sgnerd@yahoo.com.sg>
To: "sad" <sad@bankir.ru>; <pgsql-sql@postgresql.org>
Sent: Tuesday, February 17, 2004 10:40 AM
Subject: Re: [SQL] Getting the week of a date
> Seems a part of your function always returns '0'
> select 1 - (to_char(date_trunc('month',now()),'D'))::INT2
>
> because while we use date_trunc it will always return the first day of the
> month and when it get subtracted by '1' it be always zero. Is there any
> reason why you have included that?
>
> Thanks
> Kumar
>
> ----- Original Message -----
> From: "sad" <sad@bankir.ru>
> To: <pgsql-sql@postgresql.org>
> Sent: Monday, February 16, 2004 6:53 PM
> Subject: Re: [SQL] Getting the week of a date
>
>
> EXCUSE ME, GUYS !
>
> i forgot to add one monome:
> 7*(((to_char(date_trunc('month',now()),'D'))::INT2-1)/4)
> which is stands for skip a first week of month in case it is not consist
Wed
>
> finally the select will be similar the following
>
> SELECT 7*(((to_char(date_trunc('month',now()),'D'))::INT2-1)/4) + 1 -
> (to_char(date_trunc('month',now()),'D'))::INT2 + 7*3-3 ;
>
> 4 - is a number of Wed in a week (in postgresql numeration)
>
>
>
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