Re: "record" datatype - plpgsql
От | George Weaver |
---|---|
Тема | Re: "record" datatype - plpgsql |
Дата | |
Msg-id | 006401c32629$7e049510$0100007f@cleartag обсуждение исходный текст |
Ответ на | "record" datatype - plpgsql (Brian Knox <laotse@aol.net>) |
Список | pgsql-sql |
Brian, You can also use the "record" type as well in the same way. George ----- Original Message ----- From: "George Weaver" <georgew1@mts.net> To: "Brian Knox" <laotse@aol.net>; <pgsql-sql@postgresql.org> Sent: Thursday, May 29, 2003 2:01 PM Subject: Re: [SQL] "record" datatype - plpgsql > Hi Brian; > > Assuming "NEW" has been declared as foo%rowtype, you can access the > columns thus > > NEW.xxx where xxx is the column name > > HTH. > George > > ----- Original Message ----- > From: "Brian Knox" <laotse@aol.net> > To: <pgsql-sql@postgresql.org> > Sent: Thursday, May 29, 2003 11:11 AM > Subject: [SQL] "record" datatype - plpgsql > > > > Given a variable of the "record" data type in pl/pgsql, is it possible to > > get the names of the columns ( attributes ) of that record? > > > > eg, given record "NEW" for table "foo", is there a way to get information > > concerning the columns that make up that record? > > > > Brian Knox > > > > ---------------------------(end of broadcast)--------------------------- > > TIP 5: Have you checked our extensive FAQ? > > > > http://www.postgresql.org/docs/faqs/FAQ.html > > > > > ---------------------------(end of broadcast)--------------------------- > TIP 2: you can get off all lists at once with the unregister command > (send "unregister YourEmailAddressHere" to majordomo@postgresql.org) >
В списке pgsql-sql по дате отправления: