Re: create index on function - why?
От | David Huselid |
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Тема | Re: create index on function - why? |
Дата | |
Msg-id | 004901c1b64a$c32e4870$9801a8c0@TELLURIUM обсуждение исходный текст |
Ответ на | Re: create index on function - why? (Tom Lane <tgl@sss.pgh.pa.us>) |
Ответы |
Re: create index on function - why?
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Список | pgsql-sql |
Hi All, Following the advice given below, I am trying to create an index on the function upper() when used on a lastname varchar(60) column. PostgreSQL 7.0.2 Create table members (lastname varchar(60)); Then I am creating the index as: Create index upper_lastname_idx on members (upper(lastname)); But I am getting the following error: ERROR: DefineIndex: function 'upper(varchar)' does not exist I use the upper() function frequently and it works just fine, I just want the search to use the index instead of a seq scan. Thanks in advance. Dave -----Original Message----- From: pgsql-sql-owner@postgresql.org [mailto:pgsql-sql-owner@postgresql.org] On Behalf Of Tom Lane Sent: Friday, February 15, 2002 11:47 AM To: wweng@kencast.com Cc: pgsql-sql@postgresql.org Subject: Re: [SQL] create index on function - why? Wei Weng <wweng@kencast.com> writes: > But what is the rationale behind creating index on a function? To speed up searching. For example, given create table foo (f1 text); create index fooi on foo (upper(f1)); the index can be used for queries like select * from foo where upper(f1) = 'HELLO'; Without the index, there'd be no way to avoid a sequential scan --- not to mention evaluation of the function at every row. With the index, the above query actually performs zero evaluations of upper() --- the work got pushed into row insertion, instead. A functional index is sort of like a hidden, precomputed column added to your table. regards, tom lane ---------------------------(end of broadcast)--------------------------- TIP 2: you can get off all lists at once with the unregister command (send "unregister YourEmailAddressHere" to majordomo@postgresql.org)
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