question re. count, group by, and having
| От | Rick Schumeyer |
|---|---|
| Тема | question re. count, group by, and having |
| Дата | |
| Msg-id | 000b01c5ce62$514db090$0300a8c0@dell8200 обсуждение исходный текст |
| Ответы |
Re: question re. count, group by, and having
Re: question re. count, group by, and having Re: question re. count, group by, and having |
| Список | pgsql-sql |
The following query returns an error (“column c does not exist”) in pg 8.0.3:
(The column ‘state’ is the two letter abbreviation for a US state)
-- get the number of rows for each state; list in descending order; include only states with at least 6 rows
select state, count(state) as c from t group by state having c > 5 order by c desc; -- gives error
If I leave the having clause out, I get the expected results:
select state, count(state) as c from t group by state order by c desc; -- this works
Is this a bug or a feature? I’m not sure why I can use ‘c’ in the order by clause but not the having clause. pg is much happier with the full “having count(state) > 5”. Will this cause count to be evaluated twice?
If it matters, state is varchar(2).
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