Re: Subquery to select max(date) value

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От
Rich Shepard
Тема
Re: Subquery to select max(date) value
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Msg-id
alpine.LNX.2.20.1903281612410.19962@salmo.appl-ecosys.com
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Subquery to select max(date) value Rich Shepard <rshepard@appl-ecosys.com>
Re: Subquery to select max(date) value Jan Kohnert <nospam001-lists@jan-kohnert.de>
Re: Subquery to select max(date) value "David G. Johnston" <david.g.johnston@gmail.com>
Re: Subquery to select max(date) value [RESOLVED] Rich Shepard <rshepard@appl-ecosys.com>
Re: Subquery to select max(date) value Matt Zagrabelny <mzagrabe@d.umn.edu>
On Thu, 28 Mar 2019, Ken Tanzer wrote:

> You need the ORDER BY in the outer join.

Ken,

I thought so. But, ...

> (And I don't think the one inside the lateral join is doing you any good).
> Try:
> ...
>              a.next_contact is not null
>             limit 1) sq
>            order by sq.next_contact DESC;

This re-orders the returned set, but still not in chronological order.

Thanks,

Rich


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