Обсуждение: Date question

How do I convert a postrgesql timestamp
To an english date

E.g.
    $order_date = "2003-09-10 09:40:30+01";
    $date = date("d/M/Y", $order_date);
    print($date);

At 05:46 AM 9/10/03, Grant Henderson wrote:

>How do I convert a postrgesql timestamp
>To an english date
>
>E.g.
>         $order_date = "2003-09-10 09:40:30+01";
>         $date = date("d/M/Y", $order_date);
>         print($date);


The input to php "date" function is a unix timestamp, not a string.
Use:
         select date_part('epoch',order_date) from ...
instead of
         select order_date from ...





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On Wed, 10 Sep 2003, Grant Henderson wrote:

> How do I convert a postrgesql timestamp
> To an english date
>
> E.g.
>     $order_date = "2003-09-10 09:40:30+01";
>     $date = date("d/M/Y", $order_date);
>     print($date);

You can either split out the parts and use mktime to get a timestamp, then
feed that timestamp to date(), or you can do it in postgresql with
something like SET DateStyle TO 'US' and then see how they come out.

Finally, you could use the extract() function to pull the date in the
format you want ahead of time:

select extract(YEAR from field)||'/'||extract(MONTH from
field)||'/'||extract(day from field);

And get it that way.

Grant Henderson wrote:
> How do I convert a postrgesql timestamp
> To an english date
>
> E.g.
>     $order_date = "2003-09-10 09:40:30+01";
>     $date = date("d/M/Y", $order_date);
>     print($date);
>

Why not just do it in the database before you get to the PHP?


=# SELECT to_char(now(), 'Month-fmdd-yyyy'::text);

       to_char
-------------------
  September-10-2003
(1 row)


More info:

http://www.postgresql.org/docs/7/interactive/functions2976.htm

Hope that can help,

-Robby





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Robby Russell,  |  Sr. Administrator / Lead Programmer
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