Обсуждение: How I can get the real data type result instead of integer data type?

In a query, there is something like

order by count(id)/age

where both id and age are the integer data type.

From a query result, I believe the operation count(id)/age yields a integer. I need it in real data type. After
searchingthe online document, I haven't found any related information. Can someone help me out on this problem, please. 

Thanks,

w

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On Mon, 2006-03-20 at 21:10, Wei Wei wrote:
> In a query, there is something like
>
> order by count(id)/age
>
> where both id and age are the integer data type.
>
> >From a query result, I believe the operation count(id)/age yields a integer. I need it in real data type. After
searchingthe online document, I haven't found any related information. Can someone help me out on this problem, please. 
>
> Thanks,
>
> w

Try:

order by count(id)/age::float

regards,
Sig.Gunn

On Mon, Mar 20, 2006 at 13:10:51 -0800,
  Wei Wei <wei725@lycos.com> wrote:
> In a query, there is something like
>
> order by count(id)/age
>
> where both id and age are the integer data type.
>
> From a query result, I believe the operation count(id)/age yields a integer. I need it in real data type. After
searchingthe online document, I haven't found any related information. Can someone help me out on this problem, please. 

You can cast the expressions. Something like:
order by count(id)::float/age::float

"Sigurdur Gunnlaugsson" <sig@fjolnet.net>
> On Mon, 2006-03-20 at 21:10, Wei Wei wrote:
>
> Try:
>
> order by count(id)/age::float

Or you can use the standard grammer:

order by cast(count(id)/age as float)

Regards,
William ZHANG

On Tue, Mar 21, 2006 at 21:16:03 +0800,
  William ZHANG <uniware@zedware.org> wrote:
>
> "Sigurdur Gunnlaugsson" <sig@fjolnet.net>
> > On Mon, 2006-03-20 at 21:10, Wei Wei wrote:
> >
> > Try:
> >
> > order by count(id)/age::float
>
> Or you can use the standard grammer:
>
> order by cast(count(id)/age as float)

Don't you have to cast before the divide? I think the above will convert
the truncated result to float.
However he could do something like:
order by count(id)/cast(age as float)

Bruno Wolff III <bruno@wolff.to> writes:
>>> Try:
>>> order by count(id)/age::float
>>
>> Or you can use the standard grammer:
>>
>> order by cast(count(id)/age as float)

> Don't you have to cast before the divide?

Yeah.  The :: case is OK because :: binds more tightly than /
but the second suggestion is wrong :-(

            regards, tom lane