Re: Syntax problem for a newbie

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От
Tom Lane
Тема
Re: Syntax problem for a newbie
Дата
в 13:49:13
Msg-id
25985.1146847741@sss.pgh.pa.us
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Syntax problem for a newbie "Fred" <frederic.fleche@gmail.com>
Re: Syntax problem for a newbie Tom Lane <tgl@sss.pgh.pa.us>
Re: Syntax problem for a newbie Russ Brown <pickscrape@gmail.com>
Re: Syntax problem for a newbie Tom Lane <tgl@sss.pgh.pa.us>
Re: Syntax problem for a newbie Tony Caduto <tony_caduto@amsoftwaredesign.com>
"Fred"  writes:
> I have a syntax problem but I don't find the clue.
> Actually I adapt an mySQL query to a postgreSQL but I got a message
> error that I can't interpret.

> SELECT g.id, t1.name, substring(g.path, 1, (6*(-1+l.id)) + 5) as
> subpath,l.id-1 as level
> FROM  graph_path g
>     INNER JOIN term AS t1
>     INNER JOIN term AS t2  ON (t2.id = g.term2_id)
>     INNER JOIN levels l ON (substring(path, 1+(6*(-1+l.id)), 5) = t1.id
>  AND g.distance+1 >= l.id)
> WHERE t2.name = 'blood_coagulation' and g.term1_id=1
> ORDER BY g.id, subpath;

You're short an ON condition: there has to be an ON for every JOIN.
Or turn the first INNER JOIN into a CROSS JOIN, so it doesn't need an ON.

Does MySQL really accept that as-is?  (Standards compliance was never
their strong point :-()

			regards, tom lane
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