Re: Variable column name
От
Bill Moran
Тема
Re: Variable column name
Дата
Msg-id
20110902135308.97d80d35.wmoran@potentialtech.com
Ответ на
Re: Variable column name (Bob Pawley)
Список
Дерево обсуждения
Variable column name "Bob Pawley" <rjpawley@shaw.ca>
Re: Variable column name Bill Moran <wmoran@potentialtech.com>
Re: Variable column name "Bob Pawley" <rjpawley@shaw.ca>
Re: Variable column name Adrian Klaver <adrian.klaver@gmail.com>
Re: Variable column name Bill Moran <wmoran@potentialtech.com>
Re: Variable column name "Bob Pawley" <rjpawley@shaw.ca>
Re: Variable column name Bill Moran <wmoran@potentialtech.com>
Re: Variable column name "Bob Pawley" <rjpawley@shaw.ca>
Re: Variable column name Scott Ribe <scott_ribe@elevated-dev.com>
Re: Variable column name Raymond O'Donnell <rod@iol.ie>
Re: Variable column name "Bob Pawley" <rjpawley@shaw.ca>
Re: Variable column name Scott Ribe <scott_ribe@elevated-dev.com>
In response to "Bob Pawley" : > > I am getting an error -- "column "1" does not exist" > Select "1" into column ; Where are you selecting "1" from? This query has no FROM clause, so of course the column doesn't exist. The previous query, "SELECT 2 INTO point_array" is going to put the integer value 2 into the variable point_array, which I'm guessing is not what you want either. -- Bill Moran http://www.potentialtech.com http://people.collaborativefusion.com/~wmoran/
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