Thanks Buddy, really appreciate ur help on this
....problem solved...
Is there any way this query can be optimized...i'm running it on a huge table with joins
- Sumeet
On 2/23/07, Rajesh Kumar Mallah <mallah.rajesh@gmail.com> wrote:
On 2/24/07, Sumeet <asumeet@gmail.com> wrote:
> Hi all,
>
> I'm trying to write a query to select random values from a set of 'GROUP
> BY'
> ....see the scenario below to understand the problem here (the actual
> problem cannot be discussed here so i'm taking an example scenario)
>
> Assume there is a table
>
> id | name | year_of_birth
>
> query: I want to select for each year_of_birth a random name.
Dear Sumeet
postgresql DISTINCT ON may be of help , but its not standard sql.
regds
mallah.
tradein_clients=> SELECT * from temp.test;
+----+------+-----+
| id | name | yob |
+----+------+-----+
| 1 | A | 2 |
| 2 | B | 2 |
| 3 | C | 2 |
| 4 | D | 1 |
| 5 | E | 1 |
| 6 | F | 1 |
+----+------+-----+
(6 rows)
tradein_clients=> SELECT distinct on (yob) id,name,yob from temp.test order by yob,random();
+----+------+-----+
| id | name | yob |
+----+------+-----+
| 5 | E | 1 |
| 1 | A | 2 |
+----+------+-----+
(2 rows)
tradein_clients=> SELECT distinct on (yob) id,name,yob from temp.test order by yob,random();
+----+------+-----+
| id | name | yob |
+----+------+-----+
| 4 | D | 1 |
| 1 | A | 2 |
+----+------+-----+
(2 rows)
>
> --> so i do a group by year_of_birth, now i have a set of names, is there
> any function to select just one name from these set of names.
> The current approach i'm using to solve this problem is
>
> 1) getting these names in a single string using a custom function
> 'group_concat'
> 2) Convert the single string into an array
> 3) use postgresql random function to generate a random number
> 4) us the random number to select a element from the array previously
> created.
>
> The solution is there but it's kinda hack, is there any other better way of
> solving this problem.
>
>
> Thanks,
> Sumeet
--
Thanks,
Sumeet Ambre
Master of Information Science Candidate,
Indiana University.