Re: Adding to a date
| От | Steve Crawford |
|---|---|
| Тема | Re: Adding to a date |
| Дата | |
| Msg-id | 48695812.9060400@pinpointresearch.com обсуждение исходный текст |
| Ответ на | Adding to a date ("Mike Ellsworth" <younicycle@gmail.com>) |
| Ответы |
Re: Adding to a date
|
| Список | pgsql-novice |
Mike Ellsworth wrote:
> I was beginning to create some financial functions for calculating
> Future Values, PV's, etc...
>
> I'm hoping there is a way to:
> 1) Date of birth + xx years - with a result of date (Result 1)
> 2) Subtract now or an assumed date from Result 1 to get Result 2
>
Problems like 1 and 2 are easy - use "intervals".
select '1943-06-30'::date + '65 years'::interval;
2008-06-30 00:00:00
select current_date + '65 years'::interval;
2073-06-30 00:00:00
> 3) Divide by ~ 365.25 for years, which would be 'periods' in the function.
>
select ('2008-06-30'::date - '1943-06-30'::date)/365.25;
65.0020533880903491
Though there may be a better method for this. I'd need to poke around in
the date arithmetic.
Cheers,
Steve
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