extract or date_part on an interval? How many e

Hmm.  Seemed so simple.  But how do I get the number of years an
interval represents?  extract is clearly the wrong way:

stage=# select 'now()-'1987-02-01' as interval,extract(year from
now()-'1987-02-01') as age;       interval          | age
--------------------------+-----
7665 days 18:05:51.660345 |   0

select EXTRACT(year FROM INTERVAL '7665 days'); gives the same result.

select EXTRACT(day FROM now()-'1987-02-01')/365 as age; seems messy.
select (now()-'1987-02-01')/365; gives extraneous junk.
Thanks!

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