Re: psycopg3, prepared statements

On 12/23/20 4:14 PM, Daniele Varrazzo wrote:
> On Wed, 23 Dec 2020 at 23:23, Vladimir Ryabtsev <greatvovan@gmail.com> wrote:
>>
>> Cause (query, types) can give more combinations than (query,)?
> 
> Yes, that's the reason
> 
>      In [1]: import psycopg3
>      In [2]: cnn = psycopg3.connect()
>      In [3]: cnn.prepare_threshold = 2
> 
>      In [4]: cnn.execute("select 1 + %s", [1]).fetchone()
>      Out[4]: (2,)
>      In [5]: cnn.execute("select 1 + %s", [None]).fetchone()
>      Out[5]: (None,)
>      In [7]: cnn.execute("select 1 + %s", [2]).fetchone()
>      Out[7]: (3,)

Alright, I was misunderstanding. I thought you where referring to 
something like:

cur.execute("select * from some table where id > %s and user_name = %s 
and current = %s", [2, 'aklaver', True])

> 
> After 3 times the expression should have been prepared, but the tally
> has been spread in two values (0 is unknown oid, 20 is int oid).
> 
>      In [8]: cnn._prepared_statements
>      Out[8]: OrderedDict([((b'select 1 + $1', (0,)), 1), ((b'select 1 +
> $1', (20,)), 2)])
> 
>      In [9]: cnn.execute("select 1 + %s", [3]).fetchone()
>      Out[9]: (4,)
> 
> However, when either key passes the threshold, eventually preparation happens.
> 
>      In [10]: cnn._prepared_statements
>      Out[10]:
>      OrderedDict([((b'select 1 + $1', (0,)), 1),
>                  ((b'select 1 + $1', (20,)), b'_pg3_0')])
> 
> _pg3_0 is the name under which that combination of query and types is
> now prepared (it is local per session).
> 
> -- Daniele
> 


-- 
Adrian Klaver
adrian.klaver@aklaver.com