Re: [HACKERS] outfuncs.c utility statement support
| От | Tom Lane |
|---|---|
| Тема | Re: [HACKERS] outfuncs.c utility statement support |
| Дата | |
| Msg-id | 31001.1497456305@sss.pgh.pa.us обсуждение |
| Ответ на | Re: [HACKERS] outfuncs.c utility statement support (Peter Eisentraut <peter.eisentraut@2ndquadrant.com>) |
| Ответы |
Re: [HACKERS] outfuncs.c utility statement support
|
| Список | pgsql-hackers |
Peter Eisentraut <peter.eisentraut@2ndquadrant.com> writes:
> So this seems to be a pretty basic bug. Some node fields of type char
> may be zero, and so printing them as a zero byte just truncates the
> whole output string. This could be fixed by printing chars like strings
> with the full escaping mechanism. See attached patch.
+1 for fixing this, but you have not handled the read side correctly.
pg_strtok doesn't promise to return a null-terminated string, so without
changes, readfuncs.c would not successfully decode a zero-byte char field.
Also it would do the wrong thing for any character code that outToken had
decided to prefix with a backslash. I think you could fix both problems
like this:
/* Read a char field (ie, one ascii character) */#define READ_CHAR_FIELD(fldname) \ token = pg_strtok(&length);
/* skip :fldname */ \ token = pg_strtok(&length); /* get field value */ \
- local_node->fldname = token[0]
+ local_node->fldname = debackslash(token, length)[0]
although that's annoyingly expensive for the normal case where no
special processing is needed. Maybe better
+ local_node->fldname = (length == 0) ? '\0' : (token[0] == '\\') ? token[1] : token[0]
regards, tom lane
В списке pgsql-hackers по дате отправления: