Re: how to generate a list of distinct scalar values from a column which type is array

am  Thu, dem 22.02.2007, um 14:25:36 +0100 mailte A. Kretschmer folgendes:
> test=*# select * from a;
>       c
> -------------
>  {aaa,bb,c}
>  {dddd,eeee}
>  {aaa,eeee}
> (3 rows)
> 
> 
> test=*# select distinct c[s] from a,  generate_series(1,3)s where c[s] is not null;
>   c
> ------
>  aaa
>  bb
>  c
>  dddd
>  eeee
> (5 rows)
> 
> 
> You need to know the greatest upper dimension of the array, in this case
> 3, for the generate_series - function.

select distinct c[s] from a,  generate_series(1,(select max(array_upper(c,1)) from a))s where c[s] is not null;

;-)


Andreas
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Andreas Kretschmer
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