> >> Now that I think about it, this code could do a two-key scan backwards
> >> and stop after finding the first (last) valid tuple, but that's more
> >> than a one-line change.
> >
> > Actual logic is to find the maximum of pageno, for specified oid.
> > I do index scan on 2-keys index, specifying only one key as constraint...
> > If I do index scan forward I will get the smallest pageno first...
> > Otherwise I get the highest pageno... And this is what I want...
>
> Hmm ... probably right, but the loop logic doesn't behave that way
> right now.
Why not... Did not I explained what happend there? obj_desc->index_r is 2 key
index... I do index scan backward. Get first valid tuple... What I miss...
Can you please give me the correct one... I am totally confused... Sorry for
asking this...
--
Sincerely Yours,
Denis Perchine
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