2010/5/1 Cédric Villemain <cedric.villemain.debian@gmail.com>:
> 2010/4/28 Robert Haas <robertmhaas@gmail.com>:
>> On Mon, Apr 26, 2010 at 5:33 AM, Cédric Villemain
>> <cedric.villemain.debian@gmail.com> wrote:
>>> In the first query, the planner doesn't use the information of the 2,3,4.
>>> It just does a : I'll bet I'll have 2 rows in t1 (I think it should
>>> say 3, but it doesn't)
>>> So it divide the estimated number of rows in the t2 table by 5
>>> (different values) and multiply by 2 (rows) : 40040.
>>
>> I think it's doing something more complicated. See scalararraysel().
>>
>>> In the second query the planner use a different behavior : it did
>>> expand the value of t1.t to t2.t for each join relation and find a
>>> costless plan. (than the one using seqscan on t2)
>>
>> I think the problem here is one we've discussed before: if the query
>> planner knows that something is true of x (like, say, x =
>> ANY('{2,3,4}')) and it also knows that x = y, it doesn't infer that
>> the same thing holds of y (i.e. y = ANY('{2,3,4}') unless the thing
>> that is known to be true of x is that x is equal to some constant.
>> Tom doesn't think it would be worth the additional CPU time that it
>> would take to make these sorts of deductions. I'm not sure I believe
>> that, but I haven't tried to write the code, either.
>
> Relative to this too :
> http://archives.postgresql.org/pgsql-general/2010-05/msg00009.php ?
not, sorry ,misread about prepared statement in the other thread ...
>
>>
>> ...Robert
>>
>
>
>
> --
> Cédric Villemain
>
--
Cédric Villemain