in an earlier thread, the following query was submitted:
SELECT COUNT(*) FROM q
WHERE NOT EXISTS (SELECT 1
FROM t AS t
WHERE t.mid = q.mid);
and as part of his answer, David Johnson responded
3. Also, you are using a correlated sub-query instead of a LEFT OUTER JOIN
This interests me. How would you rewrite the correlated subquery above using the outer join?
--
e-Mail is the equivalent of a postcard written in pencil. This message may not have been sent by me, or intended for you. It may have been read or even modified while in transit. e-Mail disclaimers have the same force in law as a note passed in study hall. If your corporate attorney says that you need an disclaimer in your signature, you need a new corporate attorney.