Re: PHP-Postgres link

Hi,
I don't use pg_fetch_array. My english very bad and reading englesh documents
veri dificult for me. I use pg_result() and it is working. Look this:


It's worked. I don't have problem.

Best regards,
Serj MD


> Hi,
> I didn't get what is the exact problem/error about the part of the php code. 
> May be you should explain more....
> Any way, I had offen used pg_fetch_array function to get the data from the 
> tables. But If there is a sintax problem/error on your code,As I noticed, 
> may be you have to simply correct it by putting a ";" at the end of echo 
> instead of "."  like this :
> 
> echo pg_result($result, $i, "userindex") . " | " . pg_result($result, $i, 
> "username") . " | " .  pg_result($result, $i, "password") . " | " 
> .pg_result($result, $i, "field  4???") . " 
 " ;
> 
> 
> Hope that helps. Feel free to contact me .
> Omid Omoomi
> 
> 
> 
> >From: Serj MD 
> >To: pgsql-general@postgresql.org
> >Subject: Re: [GENERAL] PHP-Postgres link
> >Date: Wed, 12 Apr 2000 07:31:21 -0400
> >
> >Hello,
> >I don't speak english, I'm sorry
> >My example:
> >
> >$connection = pg_connect("", "", "", "users");
> >$query = pg_exec($connection, "INSERT INTO login VALUES ( '$userindex', 
> >'$uname', '$password', '1')");
> >$result = pg_exec ($connection, "select * from login");
> >$num = pgNumRows($result);
> >for($i = 0; $i < $num; $i++)
> >{
> >echo pg_result($result, $i, "userindex") . " | " . pg_result($result, $i, 
> >"username") . " | " .  pg_result($result, $i, "password") . " | " 
> >.pg_result($result, $i, "field  4???") . " 
 " .
> >}
> >
> >
> >???????????????????????????????
> >
> >Best regards,
> >Serj MD