> It is clear in this algorithm that there is no order dependency: the
> conditions for keeping or discarding a candidate are fixed before we
> start the second pass, and do not vary depending on which other
> candidates were discarded before it.
I won't argue strongly for either solution, but have the deep-seating
(but vague) feeling that a left to right resolution algorithm is easier
to explain, hence to understand, hence to predict, hence to use. An
extra pass will solve the edge case you describe in perhaps a "better"
order.
I do think that the two algorithms under discussion are better than what
we've had in the past. Comments from others?
- Thomas