Re: Identify an inherited table
| От | Tom Lane |
|---|---|
| Тема | Re: Identify an inherited table |
| Дата | |
| Msg-id | 2924.998660080@sss.pgh.pa.us обсуждение исходный текст |
| Ответ на | Identify an inherited table (Bo Lorentsen <bl@netgroup.dk>) |
| Список | pgsql-novice |
Bo Lorentsen <bl@netgroup.dk> writes:
> When using a database with inherited tables it somtimes would be nice if
> the row you are looking at is a base, a child or even a grandchild type.
> Like this :
> SELECT id, type() FROM base;
What you want is the standard system column tableoid:
regression=# create table parent (f1 int);
CREATE
regression=# insert into parent values (1);
INSERT 925961 1
regression=# create table child (f2 int) inherits(parent);
CREATE
regression=# insert into child values (11,22);
INSERT 925964 1
regression=# select tableoid,* from parent;
tableoid | f1
----------+----
925959 | 1
925962 | 11
(2 rows)
You can join against pg_class to convert the table oid to table name, eg
regression=# select c.relname, p.* from parent p, pg_class c where
regression-# c.oid = p.tableoid;
relname | f1
---------+----
parent | 1
child | 11
(2 rows)
regards, tom lane
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