Re: @ versus ~, redux

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От
Jeff Davis
Тема
Re: @ versus ~, redux
Дата
Msg-id
1157562537.20589.108.camel@dogma.v10.wvs
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Re: @ versus ~, redux Andrew - Supernews <andrew+nonews@supernews.com>
Re: @ versus ~, redux Tom Lane <tgl@sss.pgh.pa.us>
Re: @ versus ~, redux Jeff Davis <pgsql@j-davis.com>
Re: @ versus ~, redux Tom Lane <tgl@sss.pgh.pa.us>
Re: @ versus ~, redux Jeff Davis <pgsql@j-davis.com>
Re: @ versus ~, redux "Zeugswetter Andreas DCP SD" <ZeugswetterA@spardat.at>
Re: @ versus ~, redux Bruce Momjian <bruce@momjian.us>
Re: @ versus ~, redux Tom Lane <tgl@sss.pgh.pa.us>
Re: @ versus ~, redux Matteo Beccati <php@beccati.com>
Re: @ versus ~, redux Michael Glaesemann <grzm@seespotcode.net>
Re: @ versus ~, redux Tom Lane <tgl@sss.pgh.pa.us>
On Tue, 2006-09-05 at 23:00 -0400, Tom Lane wrote:
> Jeff Davis  writes:
> > On Mon, 2006-09-04 at 10:45 -0400, Tom Lane wrote:
> >> The existing geometric containment tests seem to be nonstrict, so if we
> >> wanted to leave room to add strict ones later, it might be best to
> >> settle on
> >> 
> >> x @>= y		x contains or equals y
> >> x <=@ y		x is contained in or equals y
> >> 
> >> reserving @> and <@ for future strict comparison operators.
> 
> > At first glace, it seems more intuitive to me to do:
> 
> > 	x @>= y		x contains or equals y
> > 	x =<@ y		y is contained in or equals y
> 
> Hm, I've never seen anyone spell "less than or equal to" as "=<",
> so I'm not sure where you derive "=<@" from?  Not saying "no", but
> the other seems clearer to me.

Initially it seemed strange to me because the @ switches sides but the
operator is not symmetrical.

I see what you mean. Standard <= and >= syntax, with an @ on the side of
the container. Now I'll be able to remember it at least, so I'm really
fine with anything.

Regards,Jeff Davis


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